![]() Let T1 be the time it takes the rock to reach the bottom of the well.If the water splash is heard 3 seconds after the rock was dropped, and that the speed of sound is 1100 ft / sec, approximate the height of the well. ![]() The graph below is that of h in terms of t and clearly shows that h is greater than 90 feet for t between 0.4 and 1.6 seconds.Ī rock is dropped into a well and the distance traveled is 16 t 2 feet, where t is the time.The height of the object is higher than 90 feet for.d - The object is higher than 90 feet for all values of t statisfying the inequality h > 90.The graphical meanings to the answers to parts a, b and c are shown below. So it takes 3.5 seconds fopr the object to hit the ground after it has been thrown upward. The above quadratic equation has two solutions one is negative and the second one is positive and approximately equal to 3.5 seconds.c - At the ground h = 0, hence the solution of the equation h = 0 gives the time t at which the object hits the ground.b - It takes 1 second for the object to reach it highest point.1 second after the object was thrown, it reaches its highest point (maximum value of h) which is given by.Hence for h given above the vertex is at t For a quadratic function of the form h = a t 2 + b t + c, the vertex is located at t = - b / 2a. The graph of h as a function of time t gives a parabolic shape and the maximum height h occur at the vertex of the parabola. ![]()
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